// CODE SNIPPET

# G 101.1 Example Calculation

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Determine the outdoor air rate required for a single zone AC unit serving an interior 2000 square feet (185.81 m

^{2}) conference/meeting room with a design occupancy of 100 people. The system supplies and returns air from the ceiling. (See Chapter 4 of this code for guidelines)

Solution:

In accordance with Table 403.2.2, the zone air distribution effectiveness is 1.0 since the system supplies cooling only from the ceiling. Using the rates from Table 402.1 for a con-ference/meeting room, the minimum system outdoor air rate is calculated to be:

Where:

A_{z} | = | zone floor area: the net occupiable floor area of the zone in square feet. |

P_{z} | = | zone population: The largest number of people expected to occupy the zone during typical usage. Where the number of people expected to occupy the zone fluctuates, P shall be permitted to be estimated based on averaging approaches described in Section 403.6.1. Where _{z}P cannot be accurately predicted during design, it shall be estimated based on the zone floor area and the default occupant density in accordance with Table 402.1._{z} |

R_{p} | = | outdoor airflow rate required per person in accordance with Table 402.1. |

R_{a} | = | outdoor airflow rate required per unit area in accordance with Table 402.1. |

E_{z} | = | zone air distribution effectiveness in accordance with Table 403.2.2. |

For SI units: 1 square foot = 0.0929 m^{2}, 1 cubic foot per minute = 0.00047 m^{3}/s

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