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// CODE SNIPPET

A.6.5 Example 5: Calculating Pressure Drops Due to Temperature Changes

2015 Michigan Residential Code > A Sizing and Capacities of Gas Piping > A.6 Examples of Piping System Design and Sizing > A.6.5 Example 5: Calculating Pressure Drops Due to Temperature Changes
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A test piping system is installed on a warm autumn afternoon when the temperature is 70°F (21°C). In accordance with local custom, the new piping system is subjected to an air pressure test at 20 psig (138 kPa). Overnight, the temperature drops and when the inspector shows up first thing in the morning the temperature is 40°F (4°C).

     If the volume of the piping system is unchanged, then the formula based on Boyle's and Charles' Jaw for determining the new pressure at a reduced temperature is as follows:

where:
T1 = Initial temperature, absolute (T1 + 459)
T2 = Final temperature, absolute (T2 + 459)
P1 = Initial pressure, psia (P1 + 14.7)
P2 = Final pressure, psia (P2 + 14.7)
P2 = 32.7 - 14.7
P2 = 18 psig


     Therefore, the gauge could be expected to register 18 psig (124 kPa) when the ambient temperature is 40°F (4°C).

Related Code Sections


A.6.5 Sizing and Capacities of Gas Piping, Example 5: Calculating Pressure Drops Due to Temperature Changes
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